If tare weight is 1,200 lb at 24 inches, and a 360 lb payload is placed at 60 inches, what is the new center of gravity in inches?

If tare weight is 1,200 lb at 24 inches, and a 360 lb payload is placed at 60 inches, what is the new center of gravity in inches?

• A. 29.0 inches
• B. 32.3 inches
• C. 31.0 inches
• D. 33.0 inches

Answer: (B)

Center of gravity is found by weighting each location by its mass and averaging those positions. Multiply each weight by its distance from the reference datum to get moments, add those moments, then divide by the total weight to get the new CG. Tare moment: 1200 lb × 24 in = 28,800 in-lb Payload moment: 360 lb × 60 in = 21,600 in-lb Total moment = 50,400 in-lb Total weight = 1200 lb + 360 lb = 1,560 lb CG = 50,400 in-lb ÷ 1,560 lb ≈ 32.31 in So the new center of gravity is about 32.3 inches from the reference datum.

Center of gravity is found by weighting each location by its mass and averaging those positions. Multiply each weight by its distance from the reference datum to get moments, add those moments, then divide by the total weight to get the new CG.

Tare moment: 1200 lb × 24 in = 28,800 in-lb

Payload moment: 360 lb × 60 in = 21,600 in-lb

Total moment = 50,400 in-lb

Total weight = 1200 lb + 360 lb = 1,560 lb

CG = 50,400 in-lb ÷ 1,560 lb ≈ 32.31 in

So the new center of gravity is about 32.3 inches from the reference datum.